-3m^2=-10m-48

Solution for -3m^2=-10m-48 equation:

-3m^2=-10m-48

We move all terms to the left:

-3m^2-(-10m-48)=0

We get rid of parentheses

-3m^2+10m+48=0

a = -3; b = 10; c = +48;
Δ = b2-4ac
Δ = 102-4·(-3)·48
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*-3}=\frac{-36}{-6}
=+6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*-3}=\frac{16}{-6}
=-2+2/3
$